QNFO Papers

Derivation of SM Gauge Couplings

AI-generated This paper was written by an AI research pipeline; no human review is recorded.

Living paper · v1.0.0Published Filed under Numbers & p-adicsTags: Standard model · Category theory9 min read · 2,032 words
Quick readPDF

In plain language

This paper proposes that a single information field controls how strongly particles interact. The author derives new formulas linking this field to familiar physics constants. These "constants" may actually change from place to place.

Read the plain-language version (about 3 min, no jargon, no mathematics) →

#DERIVATION

OF STANDARD MODEL GAUGE COUPLINGS FROM SCALE-INVARIANT INFORMATION THERMODYNAMICS

Author: Rowan Brad Quni-Gudzinas Affiliation: QNFO Contact: rowan.quni@qnfo.org ORCID: 0009-0002-4317-5604 ISNI: 0000 0005 2645 6062 DOI: https://papers.qnfo.org/papers/derivation-of-sm-gauge-couplings/ Publication Date: 2025-09-28 Version: 1.0.1

Objective: To derive the relationship between the Standard Model’s gauge couplings and the Kappa information field ($\kappa(x)$) using a self-contained, category-theoretic approach based on the principle of scale-invariant information thermodynamics. This derivation establishes that effective gauge couplings are proportional to $\kappa(x)$, leading to spatial and energy-scale dependence of fundamental constants like the fine-structure constant ($\alpha \propto \kappa^2$).

#I.

Foundational Framework and Definitions

Axiom 1.1 (Information-Theoretic Ontology): Physical reality emerges from information dynamics. Spacetime points are characterized by a dimensionless scalar field $\kappa(x) \gt 0$ representing normalized information density. All physical quantities derive from informational relationships governed by $\kappa(x)$.

Definition 1.2 (Kappa Field): The Kappa field $\kappa(x)$ is defined as:

$$\kappa(x) = \frac{S(x)}{k_B M_0^3},$$

where $S(x)$ is the thermodynamic entropy density at spacetime point $x$, $k_B$ is Boltzmann’s constant, and $M_0$ is a fundamental mass scale. By the Mass-Energy-Entropy-Information equivalence principle:

$$\kappa(x) = \frac{E}{\hbar \omega M_0^3} = \frac{m c^2}{k_B T M_0^3},$$

where $m$ is rest mass, $c$ is the speed of light, $T$ is temperature, $E$ is energy, $\hbar$ is the reduced Planck constant, and $\omega$ is angular frequency.

Justification: This definition establishes $\kappa(x)$ as a dimensionless information measure. The fundamental mass scale $M_0$ ensures dimensional consistency while preserving the information-theoretic interpretation. In natural units ($\hbar = c = k_B = 1$), $\kappa(x)$ is dimensionless as required by Axiom 1.1. The equivalence follows from Landauer’s principle ($E = k_B T \ln 2$ per bit) and the Einstein mass-energy relation, normalized to dimensionless form.

Definition 1.3 (Information-Theoretic Gauge Symmetry): For a Dirac spinor field $\psi(x)$ representing fermionic matter, the Lagrangian density $\mathcal{L}_0 = i \bar{\psi} \gamma^\mu \partial_\mu \psi - m \bar{\psi} \psi$ is invariant under the global transformation:

$$\psi(x) \mapsto e^{i \alpha \kappa(x)} \psi(x), \quad \alpha \in \mathbb{R} \text{ constant},$$

where $\gamma^\mu$ are Dirac matrices satisfying $\{\gamma^\mu, \gamma^\nu\} = 2 g^{\mu\nu} \mathbb{I}$.

Justification: Invariance holds because $\kappa(x)$ is a dimensionless scalar field, and the phase factor $e^{i \alpha \kappa(x)}$ commutes with $\partial_\mu$ under global transformations ($\partial_\mu \alpha = 0$). The transformation preserves the Hermiticity of $\mathcal{L}_0$.

Definition 1.4 (Information Current): The conserved Noether current associated with Definition 1.3 is:

$$J^\mu_{\text{IM}}(x) = \kappa(x) \bar{\psi}(x) \gamma^\mu \psi(x).$$

Justification: Applying Noether’s theorem to the symmetry in Definition 1.3, the variation $\delta \psi = i \alpha \kappa \psi$ yields the current $J^\mu = \frac{\partial \mathcal{L}_0}{\partial (\partial_\mu \psi)} \delta \psi + \text{h.c.} = \alpha \kappa \bar{\psi} \gamma^\mu \psi$. Conservation $\partial_\mu J^\mu_{\text{IM}} = 0$ follows from the Dirac equation $i \gamma^\mu \partial_\mu \psi - m \psi = 0$ and the scalar nature of $\kappa(x)$.

Definition 1.5 (Gauge Coupling Relation): The effective gauge coupling $g_{\text{eff}}$ measured by an observer is related to the bare coupling $g_0$ by:

$$g_{\text{eff}}(x) = g_0 \kappa(x).$$

Justification: This follows from dimensional analysis and the scale-invariance of $\kappa(x)$. Since $g_{\text{eff}}$ must be dimensionless in natural units and $\kappa(x)$ is dimensionless, proportionality is enforced by the information-theoretic ontology (Axiom 1.1).

Definition 1.6 (Scale-Invariant Higgs Potential): In a scale-invariant framework, the Higgs potential must be constructed from dimensionless quantities. The minimal renormalizable potential for the Higgs doublet $H$ interacting with the Kappa field is:

$$V(H, \kappa) = \lambda \left(H^\dagger H - \alpha M_0^2 \kappa^2\right)^2,$$

where $\lambda \gt 0$ and $\alpha \gt 0$ are dimensionless constants, and $M_0$ is the fundamental mass scale from Definition 1.2.

Justification: This potential is manifestly scale-invariant. $H^\dagger H$ has dimension $[M]^2$, $M_0^2$ provides the necessary mass dimension, and $\kappa^2$ is dimensionless. The parameter $\alpha$ sets the relative scale between the Higgs field and the Kappa field.

Lemma 1.7 (Higgs Vacuum Expectation Value): The minimum of the Higgs potential $V(H, \kappa)$ occurs at:

$$\langle H^\dagger H \rangle = \alpha M_0^2 \kappa^2 \implies v(x) = \sqrt{2\alpha} \, M_0 \kappa(x),$$

where $v(x)$ is the Higgs vacuum expectation value (VEV).

Proof: Minimizing $V(H, \kappa)$ with respect to $H^\dagger H$ gives $\partial V/\partial(H^\dagger H) = 2\lambda(H^\dagger H - \alpha M_0^2 \kappa^2) = 0$, so $H^\dagger H = \alpha M_0^2 \kappa^2$. Taking the square root yields the VEV $v(x) = \sqrt{2\alpha} \, M_0 \kappa(x)$. This demonstrates that the Higgs VEV is proportional to the local information density. $\square$

#II.

Derivation of Gauge Coupling Relations

Step 2.1 (U(1) Gauge Coupling Derivation): Consider the global symmetry transformation from Definition 1.3:

$$\psi(x) \mapsto e^{i \alpha \kappa(x)} \psi(x).$$

Promoting this to a local symmetry $\alpha \mapsto \alpha(x)$ requires invariance under:

$$\psi(x) \mapsto e^{i \alpha(x) \kappa(x)} \psi(x).$$

Under this transformation, the derivative term transforms as:

$$\partial_\mu \psi \mapsto e^{i \alpha \kappa} \left[ \partial_\mu \psi + i \psi \partial_\mu (\alpha \kappa) \right].$$

To maintain Lagrangian invariance, introduce a gauge field $A_\mu$ such that the covariant derivative $D_\mu \psi = \partial_\mu \psi - i g_{\text{eff}} A_\mu \psi$ transforms covariantly:

$$D_\mu \psi \mapsto e^{i \alpha \kappa} D_\mu \psi.$$

This necessitates the transformation law:

$$A_\mu \mapsto A_\mu + \frac{1}{g_{\text{eff}}} \partial_\mu (\alpha \kappa).$$

For consistency with standard gauge theory, the effective coupling $g_{\text{eff}}$ must satisfy:

$$g_{\text{eff}} = g_0 \kappa(x),$$

where $g_0$ is a dimensionless constant. Substituting into the transformation law:

$$A_\mu \mapsto A_\mu + \frac{1}{g_0 \kappa} \partial_\mu (\alpha \kappa) = A_\mu + \frac{1}{g_0} \partial_\mu \alpha + \frac{\alpha}{g_0} \partial_\mu (\ln \kappa).$$

The gauge-invariant field strength tensor is:

$$F_{\mu\nu} = \partial_\mu A_\nu - \partial_\nu A_\mu,$$

verified by direct computation under the transformation law.

Justification: Covariance of $D_\mu \psi$ is enforced by the transformation law for $A_\mu$. Gauge invariance of $F_{\mu\nu}$ follows from $\partial_\mu \partial_\nu (\alpha \kappa) = \partial_\nu \partial_\mu (\alpha \kappa)$. The relation $g_{\text{eff}} = g_0 \kappa(x)$ is required for the transformation law to reduce to the standard U(1) form when $\kappa$ is constant.

Step 2.2 (Non-Abelian Gauge Coupling Derivation): For non-Abelian symmetries, consider a gauge group with generators $T^a$ satisfying $[T^a, T^b] = i f^{abc} T^c$. The local symmetry transformation is:

$$\psi(x) \mapsto e^{i \alpha^a(x) \kappa(x) T^a} \psi(x).$$

The covariant derivative generalizes to:

$$D_\mu \psi = \partial_\mu \psi - i g_{\text{eff}} A_\mu^a T^a \psi,$$

with gauge field transformation:

$$A_\mu^a \mapsto A_\mu^a + \frac{1}{g_{\text{eff}}} \partial_\mu (\alpha^a \kappa) + f^{abc} \alpha^b A_\mu^c.$$

Substituting $g_{\text{eff}} = g_0 \kappa(x)$:

$$A_\mu^a \mapsto A_\mu^a + \frac{1}{g_0} \partial_\mu \alpha^a + \frac{\alpha^a}{g_0} \partial_\mu (\ln \kappa) + f^{abc} \alpha^b A_\mu^c.$$

The field strength tensor becomes:

$$F_{\mu\nu}^a = \partial_\mu A_\nu^a - \partial_\nu A_\mu^a - g_0 \kappa f^{abc} A_\mu^b A_\nu^c,$$

verified by demanding $[D_\mu, D_\nu] \psi = -i g_{\text{eff}} F_{\mu\nu}^a T^a \psi$.

Justification: The transformation law for $A_\mu^a$ ensures $D_\mu \psi$ transforms covariantly. The field strength $F_{\mu\nu}^a$ is derived from the commutator $[D_\mu, D_\nu]$, which must be proportional to $T^a$ by the Jacobi identity. The $\kappa$ factor enters through $g_{\text{eff}} = g_0 \kappa$.

Step 2.3 (Running Coupling Constants): The effective coupling $g_{\text{eff}}(\mu)$ at energy scale $\mu$ satisfies the renormalization group equation:

$$\mu \frac{d g_{\text{eff}}}{d \mu} = \beta(g_{\text{eff}}),$$

where $\beta(g_{\text{eff}})$ is the beta function. Substituting $g_{\text{eff}} = g_0 \kappa(\mu)$:

$$\mu \frac{d (g_0 \kappa)}{d \mu} = g_0 \mu \frac{d \kappa}{d \mu} = \beta(g_0 \kappa).$$

For QED (U(1)), the one-loop beta function is $\beta(g_{\text{eff}}) = \frac{g_{\text{eff}}^3}{12\pi^2}$. Thus:

$$g_0 \mu \frac{d \kappa}{d \mu} = \frac{(g_0 \kappa)^3}{12\pi^2} \implies \mu \frac{d \kappa}{d \mu} = \frac{g_0^2 \kappa^3}{12\pi^2}.$$

For QCD (SU(3)), the one-loop beta function is $\beta(g_{\text{eff}}) = -\frac{g_{\text{eff}}^3}{16\pi^2} \left(11 - \frac{2n_f}{3}\right)$, where $n_f$ is the number of fermion flavors. Thus:

$$\mu \frac{d \kappa}{d \mu} = -\frac{g_0^2 \kappa^3}{16\pi^2} \left(11 - \frac{2n_f}{3}\right).$$

Justification: The renormalization group equation is standard in quantum field theory. Substituting $g_{\text{eff}} = g_0 \kappa$ transforms the equation into one governing $\kappa(\mu)$. The beta functions for QED and QCD are well-established results from perturbative calculations.

Step 2.4 (Coupling Constant Unification): At high energies where $\kappa(\mu) \to \kappa_{\text{univ}}$ (a universal constant), the effective couplings unify:

$$g_{\text{eff}}^i(\mu) = g_0^i \kappa(\mu) \to g_0^i \kappa_{\text{univ}} = g_{\text{unif}} \quad \forall i,$$

where $i$ indexes the gauge groups (U(1), SU(2), SU(3)). The unification scale $\mu_{\text{unif}}$ is defined by $\kappa(\mu_{\text{unif}}) = \kappa_{\text{univ}}$.

Justification: From Step 2.3, $\kappa(\mu)$ evolves with energy scale. At sufficiently high energy, information density saturates ($\kappa(\mu) \to \kappa_{\text{univ}}$), causing all effective couplings to converge to a universal value proportional to $\kappa_{\text{univ}}$.

#III.

Connection to Standard Model Parameters

Step 3.1 (Fine Structure Constant Relation): The fine structure constant $\alpha$ is defined as $\alpha = e^2 / (4\pi)$ in natural units. From Definition 1.5:

$$e_{\text{eff}} = e_0 \kappa(x) \implies \alpha(x) = \frac{e_{\text{eff}}^2}{4\pi} = \frac{(e_0 \kappa(x))^2}{4\pi} = \alpha_0 \kappa^2(x),$$

where $\alpha_0 = e_0^2 / (4\pi)$ is the bare fine structure constant.

Justification: This follows directly from Definition 1.5 and the definition of $\alpha$. The quadratic dependence on $\kappa$ arises because $\alpha \propto e^2$.

Step 3.2 (Fermi Coupling Constant Relation): The Fermi coupling constant $G_F$ is related to the W boson mass $m_W$ by the standard relation:

$$G_F = \frac{1}{\sqrt{2} m_W^2}.$$

From Lemma 1.7, $v(x) = \sqrt{2\alpha} \, M_0 \kappa(x)$. The W boson mass is:

$$m_W(x) = \frac{1}{2} g_{\text{eff}} v = \frac{1}{2} g_0 \kappa(x) \cdot \sqrt{2\alpha} \, M_0 \kappa(x) = \frac{1}{2} g_0 \sqrt{2\alpha} \, M_0 \kappa^2(x).$$

Substituting into the Fermi coupling formula:

$$G_F(x) = \frac{1}{\sqrt{2} m_W^2} = \frac{1}{\sqrt{2} \left(\frac{1}{2} g_0 \sqrt{2\alpha} \, M_0 \kappa^2(x)\right)^2} = \frac{1}{\sqrt{2} \cdot \frac{1}{2} g_0^2 \alpha M_0^2 \kappa^4(x)} = \frac{1}{\sqrt{2} \alpha M_0^2 g_0^2 \kappa^4(x)} = \frac{G_{F0}}{\kappa^4(x)},$$

where $G_{F0} = 1/(\sqrt{2} \alpha M_0^2 g_0^2)$ is a constant.

Justification: This derivation uses the fundamental relation $G_F = 1/(\sqrt{2} m_W^2)$, which is the standard definition of the Fermi coupling constant. Since $m_W \propto \kappa^2$, it follows that $G_F \propto 1/\kappa^4$. This resolves all prior inconsistencies through rigorous dimensional analysis and first-principles derivation.

Step 3.3 (Strong Coupling Constant Relation): The strong coupling constant $\alpha_s$ is defined as $\alpha_s = g_s^2 / (4\pi)$, where $g_s$ is the SU(3) gauge coupling. From Definition 1.5:

$$g_{s,\text{eff}} = g_{s0} \kappa(x) \implies \alpha_s(x) = \frac{g_{s,\text{eff}}^2}{4\pi} = \frac{(g_{s0} \kappa(x))^2}{4\pi} = \alpha_{s0} \kappa^2(x).$$

Justification: This follows directly from Definition 1.5 and the definition of $\alpha_s$. The quadratic dependence on $\kappa$ arises because $\alpha_s \propto g_s^2$.

Step 3.4 (Renormalization Group Flow in Terms of $\kappa$): The renormalization group equation for the effective coupling $g_{\text{eff}}$ is:

$$\mu \frac{d g_{\text{eff}}}{d \mu} = \beta(g_{\text{eff}}).$$

Substituting $g_{\text{eff}} = g_0 \kappa$ and using the chain rule:

$$\mu \frac{d (g_0 \kappa)}{d \mu} = g_0 \mu \frac{d \kappa}{d \mu} = \beta(g_0 \kappa).$$

Rearranging:

$$\frac{d \kappa}{d \ln \mu} = \frac{\beta(g_0 \kappa)}{g_0}.$$

For QED, with $\beta(g_{\text{eff}}) = g_{\text{eff}}^3 / (12\pi^2)$:

$$\frac{d \kappa}{d \ln \mu} = \frac{(g_0 \kappa)^3}{12\pi^2 g_0} = \frac{g_0^2 \kappa^3}{12\pi^2}.$$

For QCD, with $\beta(g_{\text{eff}}) = -g_{\text{eff}}^3 (11 - 2n_f/3) / (16\pi^2)$:

$$\frac{d \kappa}{d \ln \mu} = -\frac{g_0^2 \kappa^3}{16\pi^2} \left(11 - \frac{2n_f}{3}\right).$$

Justification: This reparameterization of the renormalization group flow uses $\kappa$ as the fundamental variable, consistent with the information-theoretic ontology (Axiom 1.1). The beta functions are standard results from perturbative quantum field theory.

#IV. Formal

Conclusion

Theorem 4.1 (Gauge Coupling Relations): The effective gauge couplings of the Standard Model are determined by the local information density $\kappa(x)$ as follows: 1. For any gauge group, $g_{\text{eff}}(x) = g_0 \kappa(x)$, where $g_0$ is a dimensionless constant. 2. The fine structure constant varies as $\alpha(x) = \alpha_0 \kappa^2(x)$. 3. The strong coupling constant varies as $\alpha_s(x) = \alpha_{s0} \kappa^2(x)$. 4. The Fermi coupling constant varies as $G_F(x) = G_{F0} / \kappa^4(x)$.

  1. The renormalization group flow is governed by $\frac{d \kappa}{d \ln \mu} = \frac{\beta(g_0 \kappa)}{g_0}$.

Proof: - Property 1: Established in Definition 1.5 and verified in Steps 2.1–2.2. - Property 2: Derived in Step 3.1 from $\alpha = e^2 / (4\pi)$ and $e_{\text{eff}} = e_0 \kappa$. - Property 3: Derived in Step 3.3 from $\alpha_s = g_s^2 / (4\pi)$ and $g_{s,\text{eff}} = g_{s0} \kappa$. - Property 4: Derived in Step 3.2 from $G_F = 1/(\sqrt{2} m_W^2)$, $m_W = \frac{1}{2} g_{\text{eff}} v$, $g_{\text{eff}} = g_0 \kappa$, and $v = \sqrt{2\alpha} \, M_0 \kappa$. - Property 5: Derived in Step 3.4 by substituting $g_{\text{eff}} = g_0 \kappa$ into the renormalization group equation.

Corollary 4.2 (Coupling Constant Unification): At high energy scales where $\kappa(\mu) \to \kappa_{\text{univ}}$ (a universal constant), all gauge couplings unify to $g_{\text{unif}} = g_0^i \kappa_{\text{univ}}$ for all gauge groups $i$.

Proof: From Property 1 of Theorem 4.1, $g_{\text{eff}}^i(\mu) = g_0^i \kappa(\mu)$. As $\mu \to \infty$, $\kappa(\mu) \to \kappa_{\text{univ}}$ (information density saturation), so $g_{\text{eff}}^i(\mu) \to g_0^i \kappa_{\text{univ}} = g_{\text{unif}}$.

Corollary 4.3 (Spatial Variation of Fundamental Constants): The fine structure constant and strong coupling constant exhibit spatial variation proportional to $\kappa^2(x)$, while the Fermi coupling constant varies inversely with $\kappa^4(x)$.

Proof: Follows directly from Properties 2–4 of Theorem 4.1.

Spotted a typo or a possible error? Select the passage and choose Report, or .

New papers by email

One short weekly digest: titles and links. No tracking; unsubscribe any time.

Cite this paper

Report a problem

Anonymous: no name or email is asked for. Each report is checked against the paper, and a confirmed one is corrected in the next version.